go cbrt 源码

2022-07-15 浏览 (1148)

golang cbrt 代码

文件路径:/src/math/cbrt.go

/ Copyright 2009 The Go Authors. All rights reserved.
/ Use of this source code is governed by a BSD-style
/ license that can be found in the LICENSE file.

package math

/ The go code is a modified version of the original C code from
/ http://www.netlib.org/fdlibm/s_cbrt.c and came with this notice.
/
/ ====================================================
/ Copyright (C) 1993 by Sun Microsystems, Inc. All rights reserved.
/
/ Developed at SunSoft, a Sun Microsystems, Inc. business.
/ Permission to use, copy, modify, and distribute this
/ software is freely granted, provided that this notice
/ is preserved.
/ ====================================================

/ Cbrt returns the cube root of x.
/
/ Special cases are:
/
/	Cbrt(±0) = ±0
/	Cbrt(±Inf) = ±Inf
/	Cbrt(NaN) = NaN
func Cbrt(x float64) float64 {
	if haveArchCbrt {
		return archCbrt(x)
	}
	return cbrt(x)
}

func cbrt(x float64) float64 {
	const (
		B1             = 715094163                   / (682-0.03306235651)*2**20
		B2             = 696219795                   / (664-0.03306235651)*2**20
		C              = 5.42857142857142815906e-01  / 19/35     = 0x3FE15F15F15F15F1
		D              = -7.05306122448979611050e-01 / -864/1225 = 0xBFE691DE2532C834
		E              = 1.41428571428571436819e+00  / 99/70     = 0x3FF6A0EA0EA0EA0F
		F              = 1.60714285714285720630e+00  / 45/28     = 0x3FF9B6DB6DB6DB6E
		G              = 3.57142857142857150787e-01  / 5/14      = 0x3FD6DB6DB6DB6DB7
		SmallestNormal = 2.22507385850720138309e-308 / 2**-1022  = 0x0010000000000000
	)
	/ special cases
	switch {
	case x == 0 || IsNaN(x) || IsInf(x, 0):
		return x
	}

	sign := false
	if x < 0 {
		x = -x
		sign = true
	}

	/ rough cbrt to 5 bits
	t := Float64frombits(Float64bits(x)/3 + B1<<32)
	if x < SmallestNormal {
		/ subnormal number
		t = float64(1 << 54) / set t= 2**54
		t *= x
		t = Float64frombits(Float64bits(t)/3 + B2<<32)
	}

	/ new cbrt to 23 bits
	r := t * t / x
	s := C + r*t
	t *= G + F/(s+E+D/s)

	/ chop to 22 bits, make larger than cbrt(x)
	t = Float64frombits(Float64bits(t)&(0xFFFFFFFFC<<28) + 1<<30)

	/ one step newton iteration to 53 bits with error less than 0.667ulps
	s = t * t / t*t is exact
	r = x / s
	w := t + t
	r = (r - t) / (w + r) / r-s is exact
	t = t + t*r

	/ restore the sign bit
	if sign {
		t = -t
	}
	return t
}

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