spring-batch PassThroughFieldExtractor 源码
spring-batch PassThroughFieldExtractor 代码
文件路径：/spring-batch-infrastructure/src/main/java/org/springframework/batch/item/file/transform/PassThroughFieldExtractor.java
/*
* Copyright 2006-2007 the original author or authors.
*
* Licensed under the Apache License, Version 2.0 (the "License");
* you may not use this file except in compliance with the License.
* You may obtain a copy of the License at
*
* https://www.apache.org/licenses/LICENSE-2.0
*
* Unless required by applicable law or agreed to in writing, software
* distributed under the License is distributed on an "AS IS" BASIS,
* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
* See the License for the specific language governing permissions and
* limitations under the License.
*/
package org.springframework.batch.item.file.transform;
import java.util.Collection;
import java.util.Map;
/**
* {@link FieldExtractor} that just returns the original item. If the item is an array or
* collection it will be returned as is, otherwise it is wrapped in a single element
* array.
*
* @author Dave Syer
*
*/
public class PassThroughFieldExtractor<T> implements FieldExtractor<T> {
/**
* Get an array of fields as close as possible to the input. The result depends on the
* type of the input:
* <ul>
* <li>A {@link FieldSet} or array will be returned as is</li>
* <li>For a Collection the <code>toArray()</code> method will be used</li>
* <li>For a Map the <code>values()</code> will be returned as an array</li>
* <li>Otherwise it is wrapped in a single element array.</li>
* </ul>
* Note that no attempt is made to sort the values, so passing in an unordered
* collection or map is probably a bad idea. Spring often gives you an ordered Map
* (e.g. if extracting data from a generic query using JDBC), so check the
* documentation for whatever is being used to generate the input.
* @param item the object to convert
* @return an array of objects as close as possible to the original item
*/
@Override
public Object[] extract(T item) {
if (item.getClass().isArray()) {
return (Object[]) item;
}
if (item instanceof Collection<?>) {
return ((Collection<?>) item).toArray();
}
if (item instanceof Map<?, ?>) {
return ((Map<?, ?>) item).values().toArray();
}
if (item instanceof FieldSet) {
return ((FieldSet) item).getValues();
}
return new Object[] { item };
}
}
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